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48w^2-27=0
a = 48; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·48·(-27)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*48}=\frac{-72}{96} =-3/4 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*48}=\frac{72}{96} =3/4 $
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